[Math] Prove that the range is a subspace

linear algebra

In Linear Algebra Done Right, it said

If $T \in \mathcal{L}(V,W)$, then range $T$ is a subspace of $W$.

Proof:

Suppose $T \in \mathcal{L}(V,W)$. Then $T(0) = 0$, which implies that $0 \in \text{range } T$.

If $w_1,w_2 \in \text{range } T$, then there exist $v_1,v_2 \in V$ such that $Tv_1 = w_1$ and $Tv_2 = w_2$. Thus
$$T(v_1+v_2) = Tv_1 + Tv_2 = w_1 + w_2$$
Hence $w_1+w_2 \in \text{range } T$

Why $w_1+w_2 \in \text{range } T$ ? I can follow the steps but don't understand why it is in the range

Similarly, I don't understand why $\lambda w$ is in the range of $T$

Best Answer

Range of $T$ consists all vectors of the form $T(v)$ where $v \in V$. $w_1+w_2=T(v_1+v_2)$. Hence $w_1+w_2$ belongs to range of $T$. If $w=T(v)$ then $\lambda w=T(\lambda v)$ so $\lambda w$ is in the range of $T$.

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