Could anyone help me with this proof without using determinant? I tried two ways.
Let $A$ be a matrix. If $A$ has the property that each row sums to zero, then there does not exist any matrix $X$ such that $AX=I$, where $I$ denotes the identity matrix.
I then get stuck. The other way was to prove by contradiction, and I failed too.
Best Answer
Hint: You can sum the elements of a row by multiplying this row with a vector of $1$'s. Can you find now a matrix $X$ (with appropriate columns) such that $AX=Ο$?