I want to prove that $45°$ angle can be trisected for this i have to show that $\sin 15°$ or $\cos 15°$ is constructible.
How can i show that $\sin 15° \in \mathbb{Q}(\sqrt{2},\sqrt{3})$?
abstract-algebrageometric-construction
I want to prove that $45°$ angle can be trisected for this i have to show that $\sin 15°$ or $\cos 15°$ is constructible.
How can i show that $\sin 15° \in \mathbb{Q}(\sqrt{2},\sqrt{3})$?
Best Answer
Use the fact that
$$\sin{(a - b)} = \sin{a} \cos{b} - \cos{a} \sin{b}$$
with $a = 45^{\circ}$ and $b = 30^{\circ}$.