Let $$P(x) = x^4+a_3x^3+a_2x^2+a_1x+a_0$$
$$P(x_0) = 0$$
$$P'(x_0) \not= 0$$
with $x_0$ and each $a_i$ real. Prove that $P(x)$ has a at least two real roots.
I can't figure why this is true.
calculuspolynomials
Let $$P(x) = x^4+a_3x^3+a_2x^2+a_1x+a_0$$
$$P(x_0) = 0$$
$$P'(x_0) \not= 0$$
with $x_0$ and each $a_i$ real. Prove that $P(x)$ has a at least two real roots.
I can't figure why this is true.
Best Answer
Hint: have you tried sketching possible shapes for the polynomial, noting that the $x^4$ term dominates when $|x|$ is large.