Urn 1 contains 4 red chips and 3 white chips. Urn 2 contains 3 red chips and 2 white chips. 2 chips are chosen at random and without replacement from each urn. 1) What is the probability that all 4 chips will be red? and 2) What is the probability of getting 3 red chips and 1 white chip amongst the 4?
Not homework, studying for a midterm and got very confused.
For 1) I got ((4 choose 2)(3 choose 2))/((7 choose 2)(5 choose 2))
For 2), in the numerator I think I need to add all the different mutually exclusive outcomes, so (this is just the numerator): (4c1)(3c1)(3c2) + (4c2)(3c1)(2c1), over the same denominator as above – (c indicates choose).
Is this correct? I always seem to have so much trouble with these counting type questions, like the poker hands, choosing objects from urns, rolling x die and choosing a specific number of 3s,4s etc… What's a general fool-proof, methodical way to approach these problems?
Best Answer
Answered in question description...