If two six sided die with the numbers $1,0,1,2,3,4$ on each of them are rolled. What is the probability that the product of the numbers on the upmost faces is greater than the sum.
I have an answer key that states the answer to this is $11/36$, but I keep getting $8/36$. What am I missing?
Best Answer
I'm also getting the answer $8/36$, the $8$ cases being:
$(4,4),(3,4),(4,3),(2,4),(4,2),(3,3),(2,3),(3,2)$
The other answer I can see to this problem is to consider the cases where the product is greater or $\textbf{equal}$ to the sum. In this scenario, other two cases come into play:
$(2,2),(0,0)$
But in this scenario the answer would be $10/36$. Anyway, I think the right thing to say is that either your answer key is wrong, or the question was misenterpreted and I'm missing one case.