An urn contains four balls: one red, one green, one yellow, and one white.
Two balls are drawn without replacement from the urn. What is the probability of getting a red ball and a white ball? Assume that the balls are
equally likely to be drawn
Here's what I've tried:
Probability of a red or a white ball on first draw: $\frac{1}{4}$
Probability of a red or a white ball on second draw: $\frac{1}{3}$
Total Probability : $\frac{1}{4}\cdot\frac{1}{3}=.0833$, but the correct answer is $0.167$
Best Answer
Probability of getting a red or white ball on first draw:$\frac{1}{2}$
probability of getting the remaining ball that is either red or white $\frac{1}{3}$
probability both of these happen: $\frac{1}{2}\cdot \frac{1}{3}\approx0.167$