[Math] Probability in a Dice Game (Zombie Dice)

diceprobabilityproblem solving

In the game of Zombie Dice (Rules) there exist 13 dice:

  • 6 Green – 3 Brains, 2 Footprints, 1 Shotgun
  • 4 Yellow – 2 Brains, 2 Footprints, 2 Shotguns
  • 3 Red – 1 Brain , 2 Footprints, 3 Shotguns

A footprint forces the user to roll the dice again. A shotgun counts as a 'X', and 3 result in the loss of a turn.

I question what the probability of rolling 13 brains, in a single turn, assuming 13 dice total.

When calculating this myself, I assumed a probability of:
((1/6)^3) * ((1/3)^4) * ((1/2)^6)
However, a friend of mine brought up that the footprints would have an influence on the odds, which I disputed.

TLDR;
What is the impact of the footprints, and what is the total probability of rolling 13 brains?

Best Answer

Let's look at a green die.

Let p=the odds of getting brains on a green die. What are the cases when tossing one?

  1. Brains: $\dfrac12$
  2. Footprint: $\dfrac13\cdot p$

So, we get that $p=\dfrac12+\dfrac13p$. Thus $p=\dfrac34$.

Similarly, you can get the probabilities for the other two colors of dice. Then multiply them out like you did with the other probabilities.