As title describes, I was wondering how I would put this into Cartesian form, from polar.
All I have is $ r = \sin(2\theta)$.
I'm not really sure what to do, I've been trying to find similar problems on the internet to no avail (at least with an explanation), nor can I figure it out myself. Any help would be great.
Best Answer
$r = \sin(2\theta) = 2\sin\theta\cdot \cos\theta \to r^3 = 2(r\sin\theta)(r\cos\theta)$. Then use:
$x = r\cos\theta$, and $y = r\sin\theta$, and $r = \sqrt{x^2 + y^2}$ to finish.