I'm doing the following homework problem and am unsure of whether or not my answers are correct. This is my first time working with Poisson distribution and I want to make sure I am doing it correctly.
Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with mean $u = 20$. What is the probability that the number of drivers will
a. Be at most 10?
b. Exceed 20?
c. Be between 10 and 20, inclusive? Be strictly between 10 and 20?
d. Be within 2 standard deviations of the mean value?
I'm pretty much just trying to follow the formula that I was given for Poisson distribution and have the following answers:
a. $P(x\le 10) = \sum{0\to10}\frac {e^{20} \times 20^x}{x!} $
b. $P(x>20) = \frac {e^{20} \times 20^(20)}{20!} $
c. $P(10 \le x \le 20) = \sum_{10\to20}\frac {e^{20} \times 20^x}{x!} $
$P(10 < x <20) = \sum_{10\to20}\frac {e^{20} \times 20^x}{x!} $
d. not sure still
Best Answer
The Poisson with parameter $\lambda$ has mean $\lambda$ (and variance $\lambda$).
So if you know the mean, you know the parameter.
For the first question, the required probability is $$\sum_{k=0}^{10} e^{-20} \frac{20^k}{k!}.$$ Note that it is $e^{-20}$, not the $e^{20}$ of the post. The same mistake recurs.
For the probability that $X\gt 20$, we could sum from $21$ to $\infty$. But that's a long sum! To evaluate it, calculate the probability that $X\le 20$, and subtract this from $1$.
For c), your sum (apart from the fact that we need $e^{-20}$) is correct. For strictly between, sum from $11$ to $19$.
For d), the standard deviation is $\sqrt{20}$. So $2$ standard deviations is about $8.944$. Find the integers that are within $8.944$ of $20$, and take the sum of the Poisson probabilities in that range.