I have just started to learn Poisson Distribution and I have no idea how to deal with the following practice from my textbook: Suppose the average amount of cars passing on a street per minute is Poisson (8.6). It takes a lady 5 seconds to cross a street and she waits for two cars to pass. What is the probability that she is safe to cross the street ?
[Math] Poisson Distribution practice problem
poisson distributionprobability
Best Answer
The lady waits for 2 cars means:
the first 5 seconds, the lady waits because there is car passing. the second 5 seconds, the lady waits because there is car passing. the third 5 seconds, the lady waits because there is no car passing.
there is no car passing is P(0)=48.8% (you can do the math) there is car passing is 1-P(0)=41.2%
so the probability is 41.2% x 41.2% x 48.8%