[Math] Orthogonal projection on an eigenspace

Question

For different symmetric matrix $A$ ( eigenspaces are orthogonals ), I've noticed that when I build the matrix of the orthogonal projection of an eigenspace I get identity. Are my calculation wrong or is it always true ?
For example with
$$A=\begin{pmatrix}
1 &2 \\
2& 1
\end{pmatrix}$$
We get the two eigenvalues are $3$ and $-1$ for two normalized eigenvector respectively $\displaystyle e_1=\frac{1}{\sqrt{2}}\left(1,1\right)$ and $\displaystyle e_2=\frac{1}{\sqrt{2}}\left(1,-1\right)$
Then the orthogonal projection $p(x)$ of $x=\left(a,b\right) \in \mathbb{R}^2$ is
$$
p\left(x\right)=\langle x,e_1\rangle e_1+\langle x,e_2\rangle e_2=\left(a,b\right)=x
$$

Answer 1

Your $p$ is not the orthogonal projection onto an eigenspace, it is the orthogonal projection onto the span of both eigenspaces. The two eigenspaces span $\Bbb R^2$, so of course that projection is the identity, being the orthogonal projection from $\Bbb R^2$ onto itself.

If $A$ is any symmetric $n\times n$ matrix then the eigenspaces of $A$ span $\Bbb R^n$.