[Math] Non-linear partial differential equation

partial differential equations

I would like to find out if there is any specific method -apart from numerics- for finding solutions of a non-linear PDE of the form

$$\nabla \times \mathbf{A} = \pm\lambda\mathbf{A} \tag{1}$$

under the constraint

$$\nabla\lambda \times \mathbf{A} = 0 \tag{2}$$

where λ is either an unknown real constant or an unknown scalar function ($\lambda(\mathbf{r})$) of a vector variable in $\mathbb{R}^3$ and $\mathbf{A}$ is a vector field in same space, which may be restricted in a curved manifold.
This problem occurs in eigenrotation flows (Euler fluids), and their application in Parallel Electric and Magnetic components of the associated Maxwell fields.
There is a large literature on this problem which starts with Eugenio Beltrami at the end of 19th century and Viktor Trkal at the beginning of the 20th century. Recent applications in plasma and E/M started with Chandrsekhar, Kendal, Lakhtakia and others for the case of solenoidal fields ($\nabla\cdot\mathbf{A} = 0$).
In the non-solenoidal case, taking the divergence of (1) results in the lhs to

$$\nabla\cdot\mathbf{A} = -\nabla(\log\lambda)\cdot\mathbf{A} \tag{3}$$

Condition (2) has the strange feature that the nth application of the Curl operator results in the simplest group structure (although the problem is nonlinear!)

$$\nabla\times\nabla\times …\nabla \mathbf{A} = {(\pm)}^n{\lambda}^n\mathbf{A} \tag{4}$$

where n is the number of application of the Curl operator.
The associated nonlinear wave equation will then will have an additional "source" term of the form $\nabla(\nabla\cdot\mathbf{A})$.
At first hand, it appears that the only solution in a Euclidean space must have constant λ but in the case of curved manifolds with a connection the problem is not trivial.

Addendum (07/05/2011)

Concerning the generality of (4) in relation to eigenrotation fields that are not Beltrami it should be mentioned that a more natural choice appears to have the form

$$\nabla\lambda \times \mathbf{A} \propto \mathbf{A}_{\perp} = \kappa(\mathbf{r})\bar{\mathbf{R}} \mathbf{A} \tag{5}$$

where the rhs denotes an appropriate projection on the plane of $\nabla\lambda$ and $\mathbf{A}$ with $\kappa$ a proportionality scalar and $\bar{\mathbf{R}}$ the relative rotation matrix.

In such a case one obtains

$$\nabla\times\nabla\times\mathbf{A} = (\kappa\bar{\mathbf{R}} \pm \lambda)\mathbf{A} \tag{6}$$

Subsequent applications of the Curl operator won't work the same as in (4) unless one can prove that there is a Ladder of functions {$\kappa_{i}$} all satisfying condition (2) or (5) or at least $\kappa = c\lambda$.

Addendum: connection w. Wave Equation (08/05/2011)

It is notable that furthe analysis of the additional source term $\nabla(\nabla\cdot\mathbf{A})$ using known vector identities as found in tables (see http://en.wikipedia.org/wiki/Vector_calculus_identities#Properties) results in two "convective" like derivatives. Using the double curl we also obtain from (1) or (6)

$$\nabla^2\mathbf{A} + \epsilon(\mathbf{r})\mathbf{A} = \mathbf{J} \tag{7}$$

where the source has the explicit form

$$\mathbf{J} = (\nabla\phi\cdot\nabla)\mathbf{A} + (\mathbf{A}\cdot\nabla)\nabla\phi \tag{8}$$

with $\lambda = e^{-\phi}$ and $\epsilon(\mathbf{r})$ is either $\pm\lambda(\mathbf{r})$ if condition (2) is satisfied or $(1+\lambda)\kappa\bar{\mathbf{R}} \pm \lambda$ if condition (5) holds. The situation now resembles a vector potential in a material with a complicated variable refractive index and possibly a very unusual optical rotation (the last may not be realizable in an actual situation though due to physical restrictions).

Best Answer

The eigenvectors of the curl operator $$\nabla \times {\bf A}$$ in Cylindrical coordinates are the Bessel functions $J_0( a r)$, you will have to plug back this in to see how $a$ depends on $\lambda$. But all this assumes $\lambda$ is a constant. In your problem, you don't have $\lambda$ constant, but special cases are sometimes useful.

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