[Math] Meaning of sampling i.i.d rvs from (random) probability measure

measure-theoryprobability theory

Quote from book: "Consider an arbitrary atomic probability measure $\Gamma$ on unit sphere. Let $(\sigma_{l})$ denote an i.i.d sample from $\Gamma$."

I don't understand the second sentence. Does it mean

Let $(\sigma_{l})$ be random variables mapping into the sphere. Then pick the ones, mapping into the support of $\Gamma$.

or

Pick points $(\sigma_{l})$ uniformly from the support of $\Gamma$.

So that in the case $\Gamma$ is a random measure (i.e. $\Gamma:\Omega\times \mathbb{S}^{n-1}\to \mathbb{R}$), the second sentence respectively says

Let $(\sigma_{l})$ be random variables mapping into the sphere. Then pick the ones, mapping into the most probable support of $\Gamma$.

or

Pick points $\sigma_{l}$ uniformly from the most probable support of $\Gamma$.

Thank you

(1)"The Sherrington-Kirkpatrick model" by D.Panchenko pg. 17

Best Answer

It means that each $\sigma_i$ is a random variable (mapping into the sphere) with distribution given by $\Gamma$. Furthermore, $\sigma_1,\dots, \sigma_n$ are (stochastically) independent for each $n$.

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