Let R be the region bounded by the parabola , $y=x^2$; and the line , $y=16$;. (a) What is the volume of the solid generated when R is rotated about the line, $y=16$ ?
I'm really lost here.
calculusintegration
Let R be the region bounded by the parabola , $y=x^2$; and the line , $y=16$;. (a) What is the volume of the solid generated when R is rotated about the line, $y=16$ ?
I'm really lost here.
Best Answer
Our method is Dishwasher: $r = 16-x^2 \to V = \displaystyle \int_{-4}^{4} \pi(16-x^2)^2dx$