[Math] Is the probability of picking an Ace as the second card of a deck the same if the deck is shuffled after the first card

card-gamescombinatoricsprobability

Here's the situation:

You have a deck of 52 cards that is already shuffled. You pick the first card, and the first card is not an Ace. Is the probability of drawing an Ace as second card the same if

  1. The second card is immediately drawn from the deck
  2. The remaining deck is first shuffled without adding the first card back in, and then the second card is drawn.

For me, it is obvious that probability of drawing an Ace in the second case is 4/51, but I'm not entirely sure that the probability is the same in the first case.

Also, what would be the probability of the first case if we have drawn n cards and none of these are aces?

Best Answer

If it's not intuitively clear, you can check your calculation using contitional probability:

  • $X$... the event "the second card is an ace"
  • $Y$... the event "the first card is not an ace"

Then, $P(X\land Y) = \frac{48\cdot 4}{52\cdot 51}$ and $P(Y) = \frac{48}{52}$

Then $$P(X|Y) = \frac{P(X\land Y)}{P(Y)} = \frac{\frac{4\cdot 48}{52\cdot 51}}{\frac{48}{52}} = \frac{4}{51}$$

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