The Problem ask about basis of null space of nxn matrix
but when I solved it I found it has trivial solution that mean every variable equal 0 and linearly independence.
But the problem ask basis for null space and vector 0 can't be basis
Can I use standard basis as basis for null space ? or this matrix has no basis for null space?
[Math] Is it possible matrix nxn matrix has no basis of null space
linear algebramatrices
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Best Answer
If you found that $\ker(A)=\{0\}$, then $\varnothing$ is a basis of $\ker(A)$.