Let $U, V$ be separable Banach spaces.
Suppose we have a bounded, linear operator
$C : U\to V$.
Questions are the following
*) Shall $C$ be continuous since $V$ is a Banach space?
*) In general, is a bounded linear operator necessarily continuous (I guess the answer is no, but what would be a counter example?)
*) Are things in Banach spaces always continuous?
Best Answer
An operator $C$ is bounded iff the set {$\|Cx\|:\|x\|\leq 1$} is bounded $\Leftrightarrow$ there is a $M<\infty:\|Cx\|\leq M\|x\|$ for every $x\in U$.
Let $ε>0$. If $x,y\in U:\|x-y\|<ε/M$, then $\|Cx-Cy\|\leq M\|x-y\|<ε$. Thus $C$ is not only continuous but uniformly continuous also.
So, a bounded operator is always continuous on norm-spaces. Banach space is a norm-space which is complete, thus things are not different there.