[Math] Irrational numbers, decimal representation

decimal-expansionirrational-numbersnumber theorytranscendence-theorytranscendental-numbers

Can this even be proved? (Or disproved?)

Any irrational number without a 0 (zero) in its decimal representation is transcendental.

Not sure where to start on this one…

Best Answer

Wikipedia says,

It has been conjectured that every irrational algebraic number is normal; while no counterexamples are known, there also exists no algebraic number that has been proven to be normal in any base.