my intuition about quadratic(degree 2) splines is that by the help of its three variables (in each sub-interval) you can make a piecewise differentiable function on the whole interval.
in the process of finding a degree 2 spline generally we need to exactly specify the derivative of ONE point and then we find a unique spline .
But since we usually need to specify the derivative of both end points then generally we cannot do this with a degree 2 spline.
so we raise the spline power to 3 . now we have 4 variables for each sub-interval .
now my intuition suggests that with this new variable we simply plug in both end point derivative conditions and we get a unique answer .
BUT instead, by adding the new variable we are ALSO able to make the second derivative continuous .
Question is
how adding one variable can handle both the endpoints derivative condition and the second derivative continuity condition ?
Best Answer
Let's count the conditions: $N+1$ points for $N$ intervals. Resulting in $4N$ coefficients of $N$ cubic polynomials. On the side of the equations we get
Which still leaves us with a difference of $2$ degrees of freedom. One usually imposes conditions on the first and last point, for instance a zero second derivative