How to input $\frac{d}{dx}(\int_0^x \sqrt{t^2-t+1} \,dt)$ in Wolfram Alpha?
If i change $dt$ by $dx$ it works, but the output is $\sqrt{t^2-t+1}$, there is no substitution for "$t$" there, if i am correct the result should be $\sqrt{x^2-x+1}$.
[Math] Input integral derivative in Wolfram Alpha
calculuswolfram alpha
Best Answer
I don't think the way around this is by changing the $dt$ to $dx$. Trying alternative routes, like suggested by Shuhao Cao, ended up exceeding standard computing time through Alpha, even extending additional computation time.
If you have Mathematica, it provides greater amounts of computation time, but in the case of your posted problem, the result is clearly $\sqrt{x^2 - x + 1}$ without the use of software.