In how many ways can five different sweets be split amongst two people if each person must have at least one sweet?
I tried $5 C 1 + 5 C 2 + 5 C 3 + 5 C 4 = 30$, however, the answer is $20$.
Any help is appreciated, thanks in advance.
[Math] In how many ways can five different sweets be split amongst two people if each person must have at least one sweet
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Best Answer
I agree with your answer of $30$...
Unless there is some other condition, such as one person gets $3$ sweets and the other person gets $2$ sweets--which would give an answer of $20$.