If the spinner is spun 2 times what is the probability that it lands on "A" both times.
My answer is 3/16 and here is how I got it:
I divided the whole circle into 8 equal parts out of which 3 parts
are of A. so the probability of landing on A would be 3/8 on first
spun. Therefore, for spinning the spinner twice then the probability
of landing it on A would be (3/8)/2=3/16
But answer key is showing 1/64 which is not matching with my answer and therefore I would like to ask experts here.
Best Answer
The chance of anding on A for one spin is $\frac{90+45}{360}=\frac{3}{8}$. So the probability of that happening twice in a row is $\frac{3}{8}\times\frac{3}{8}=\frac{9}{64}$.