if the probability a shooter hits the target is equal to .8 then the probability that the shooter will correctly hit the target after 10 failed attempt is equal ……?
probability of hitting the target after 10 is the same as 1 – the probability of failing 10 times
so P=1-(1-.8)^10
=0.9999999989
is the answer correct !
Best Answer
The probability that he hits the target on this 11th attempt is $0.8$ - you're assuming that past (independent, we assume) events have an effect on the outcome of the event.
On the other hand, the probability of that specific sequence of events, $10$ failures and $1$ success, is $$(0.2)^{10}(0.8) = 8.2\times10^{-8}$$