[Math] if one three digit number (0 cannot be left digit) is chosen at random from all those that can be made from this set that are not a multiple of 5.

Question

Set = {0,1,2,3,4,5,6}

The left digit would have 6 possibilities since 0 cannot be the left digit.
The middle one would have 7 possibilities.
The right digit would have 2 possibilities 0 and 5?

Am I correct? or totally wrong?

Answer 1

If you're not allowed to repeat digits, then there are 6 possibilities for the first digit (since it can't be zero), 6 possibilities for the second, and 5 possibilities for the third. If your number has to be a multiple of 5, then there are only 2 possibilities for the third.

Finally, if you're allowed to repeat digits and want a multiple of 5, the numbers are 6, 7, and 2, as you said.