[Math] How to solve this question of percentile and percentile groups

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The outcome of a standardized test is an integer between 151 and 200, inclusive. The percentiles of 400 test scores are calculated, and the scores are divided into corresponding percentile groups.

Quantity A] The minimum number of integers between 151 and 200 inclusive, that include more than one percentile?

Quantity B] The minimum number of percentile groups that correspond to a score of 200?

Options:

A) Quantity A > Quantity B

B) Quantity A < Quantity B

C) Quantity A = Quantity B

D) Cannot be determined


Solution as explained :

Solution part 1

Solution part 2


I did not understand this solution. Kindly help.

Best Answer

This is, in my opinion, a very confusing language the question, and therefore the solution is stated in. I believe once you understand the question well, the answer is almost immediate. Let me ask the question in a clear, but different way.

Say you have 50 baskets, numbered $1,2,\cdots, 50$ and $400$ balls. Say someone comes and distributes the balls in the baskets in a certain fashion.

Given a distribution of balls, let $M$ be the number of baskets which contain at least 1 percent of the balls. (since one percent of the balls is $400/100=4$, we are counting the number of baskets which end up with $4$ or more balls in them).

Quantity A: If you were free to distribute the balls as you please, how should you distribute them such that $M$ is as little as possible? What is $M$ in this situation? This $M$ is your quantity $A$.

Solution: We first ask: is it possible to achieve $M=0$? Well, no! Because if each basket has $\leq 4$ balls since there are $50$ baskets, the number of balls has to be $\leq 4\times 50=200$. But you have $400$ balls, not $200$.

So next we ask, OK $M=0$ is not possible but is $M=1$ possible? Yes, one easy choice is to put all $400$ balls in just one basket and leave everything else empty. As a result quantity, $A$ is $1$.

Now let's focus on just one basket, say the basket number 50 (the last one). Let $N$ be the percentage of balls this basket contains.

Quantity B: If you were free to distribute the balls as you please how should you distribute them, such that $N$ is as little as possible? What is $N$ in this situation?

Solution: Again we ask: is $N=0$ possible? Well, yes, just don't put any balls in the last basket! So quantity B is zero.

The question and the answer confusingly talk about percentile groups. A percentile group is the number of scores which make up one percent of the total scores. So the number of percentile groups belonging to a basket has is just the percentage it contains. It is rather effectively confusing terminology for this question.