[Math] How to solve this logarithmic equation whose expressions have different bases

Question

I have been trying to solve the following equation for a while and i can't seem to figure it out, your help would be greatly appreciated. Here is the equation: $3^x$=$5^{x-1}$

Answer 1

Hint: $$\log_3(5^{x-1})=(x-1)\log_3(5)$$