[Math] How to show that isometry is an equivalence relation among metric spaces

equivalence-relationsgeneral-topologymetric-spaces

Ok, to start I am new to metric spaces. I have studied equivalence relations in Algebra, but unfamiliar with the e.r. in metric spaces.

Here is my question:

We say that metric spaces (X,$d_X$) and (Y,$d_Y$) are isometric if there is an isometry $f:X \to Y$. Write this as (X,$d_X$) $\backsimeq$ (Y,$d_Y$) and show that $\backsimeq$ is an equivalence relation on the collection of metric spaces.

I know that I need to show the following

  • $x \backsimeq x$ but don't know what "x" looks like; is it $d_X (a,a)
    \backsimeq d_Y (x,x)$ if so where do "x" come from. Or, how do I
    define $\backsimeq$?
  • $x \backsimeq y \implies y \backsimeq x$ same problem as above
  • $x \backsimeq z$ and $z \backsimeq y \implies x \backsimeq z$. Which is an even bigger problem since i don't know where "z" comes from.

I am told that if I can show $f^{-1}$ preserves distance, then I am done.

If anyone can tell me what I need to show, I should be good. i.e. what "x" is and how to define $\backsimeq$.

PROOF: (As of right now. I am still over thinking this problem.)

Reflective property can be shown by the identity map. Let $id:X\to X$, then $id$ is bijective and we are done?

Symmetric property want to show $f:X\to Y$ is bijective, which will then show there is inverse to $f$; i.e. $f^{-1}:X\to Y$ which is bijective.

Let $(X,d_X)\backsimeq (Y,d_Y)$, then $f:X\to Y$ is isometry which implies that for every $y\in Y$ $\exists x\in X$ s.t. $f(x)=y$. Since $(X,d_X)$ and $(Y,d_Y)$ are isometric we have $d_X (x_1,x_2)=d_Y (y_1,y_2)=f_Y (f(x_1),f(x_2))$. Thus, for every $x\in X$ and $y\in Y$ we have $d_X(x_1,x_2)=d_Y(f(x_1),f(x_2))$. Thus, $f$ is bijective, which implies there exists an $f^{-1}$. Therefore, $(Y,d_Y)\backsimeq (X,d_X)$.

Best Answer

Your objects here are metric spaces. If in algebra you may have met the equivalence relation over $\Bbb Z$ defined by $x\equiv_3 y\iff 3\mid x-y$, and that relation was defined on integers, then this equivalence relation is defined on a collection of metric spaces.

This means that to verify that $x\simeq x$ you actually need to verify that if $(X,d_X)$ is a metric space then there exists an isometry from $X$ to itself (with the same metric!). For example the identity function.

For symmetry you need to show that if there exists $f\colon X\to Y$ which is an isometry between $(X,d_X)$ and $(Y,d_Y)$ then there exists an isometry $g\colon Y\to X$ preserving the same metrics.

Lastly, for transitivity - as before - you have to assume the existence of two isometries between three metric spaces and conclude the existence of a third.


Note that all those are really standard if you have seen proofs of equivalence relations defined by "existence of some structure preserving function".

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