[Math] How to prove that two lines are not parallel

analytic geometryvectors

Given the points in the three-dimensional affine space $A = (1, 1, 1)$, $B = (-2, -1, 0)$.

• Find the Cartesian equations of line $r$ for points $A$, $B$.

I found it and it is:

$$
\left\{
\begin{array}{c}
x-3z+2=0 \\
y-2z+1=0 \\
\end{array}
\right.
$$

Correct me if it's wrong. Now given the line $r'$ of parametric equations:

$$
\left\{
\begin{array}{c}
x=1+3t' \\
y=-2 \\
z=1-t'
\end{array}
\right.
$$

with $t'∈R$, how can I prove that the lines $r$ and $r'$ are not parallel?

Best Answer

Hint: a direction vector of the first line is given by $A-B=(3,2,1)$, while a direction vector of the second line (look at the coefficients of $t'$) is $(3,0,-1)$.