Find the vector $x$ determined by the given coordinate vector $[x]_B$ and given basis $B$:
$$
B
= \left\{
\begin{bmatrix} 3 \\ -5 \end{bmatrix},
\begin{bmatrix} -4 \\ 6 \end{bmatrix}
\right\},
\quad
[x]_B
= \begin{bmatrix} 5 \\ 3 \end{bmatrix}.
$$
I saw a couple different ways to approach this problem from tutorials on YouTube, and each led to a different answer. This is what I got:
3 -4 | 5 -5 6 | 3 3 * 5 + -4 * 3 = 3 -5 * 5 + 6 * 3 = -7 A = 3 -7 v1 = 3 -5 v2 = -4 6 3 * v1 + -7 * v2 = x = 9 + 28 -15 -42 = 37 57
Is that the correct answer?
Best Answer
This is largely a matter understanding the definition and notation. Typically if you have a basis $B=\{ \mathbf v_1, \mathbf v_2 \}$ and are told that $[\mathbf x]_B = (x_1, x_2)$ for real numbers $x_1$, $x_2$, then $\mathbf x = x_1 \mathbf v_1 + x_2 \mathbf v_2$. In our particular case, $$\mathbf x=5v_1 + 3v_2 = 5(3, -5) + 3(-4, 6) = (15, -25) + (-12, 18) = (3, -7) = 3 \mathbf e_1 - 7 \mathbf e_2$$ where $\mathbf e_1 = (1, 0)$ and $\mathbf e_2 = (0, 1)$ are the standard basis vectors for $\mathbb R^2$.