[Math] How to find the base of an isosceles triangle with the angles and legs

geometrytriangles

I want to find the base of an isosceles triangle with base angles of 54.5 degrees and legs with the lengths of 43 with geometric relationships.

Best Answer

Look at this picture http://mathworld.wolfram.com/images/eps-gif/Trigonometry_700.gif

Imagine that $\theta = 90-54.5= 35.5$.

This is a picture of your triangle cut in half, laid on its side, and shrunk to $1/43$ it's size.

We want to know what is the length of the side labeled "$\sin \theta $" is.

Your answer will be twice that multiplied by $43$.

So we plug it it into a calculator and get $\sin 35.5 = 0.58070295571093976105008.... $

So multiply that by $2$ and you will have the base of an isoceles triangle with legs of $1$.

Multiply that by $43$ and you will have the base of your tringle.

So the answer is $49.940454191140819450...... $.