The base of an Isosceles triangle is $5\text{ cm}$ longer than the height. If the area of the triangle is $12\text{ cm}^2$. Find the height, base and the length of one of its equal sides.
[Math] How to find the altitude, base and the length of a triangle
triangles
Best Answer
Since, the area is given as 12, and area of a triangle is given by $$\frac{1}{2}\times \text{base}\times \text{height}=12$$
Now, you are also given that $$\text{base}=\text{height}+5$$
So, Use the second information into the formula, generate an equation and solve it!
HINT: $\text{height}=1 \text{cm}$ $\text{base}= 6 \text{cm}$