Find the equation of the line that is tangent to the curve at the point $(0,\sqrt{\frac{\pi}{2}})$. Given your answer in slope-intercept form.
I don't know how can I get the tangent line, without a given equation!!, this is part of cal1 classes.
[Math] how to find tangent line at a given point, without equation
derivatives
Best Answer
If we suppose that your curve is the graph of a function $y=f(x)$ such that $f(0) = \sqrt{\pi/2}$, than the equation of the tangent at $x=0$ is:
$ y-\sqrt{\pi/2}=f'(0)(x-0) $
i.e.
$y=f'(0) x+\sqrt{\pi/2}$