[Math] how to find existence and value of limit in multivariable calculus

calculuslimitsmultivariable-calculuspolar coordinatesprobability-limit-theorems

I was in maths class and i found a question interesting.
Find the limit of $\lim_{(x,y)\to (0,0)} \frac{2x}{x^2+x+y^2}$ if it exist.one of my friend did this question by transforming into polar coordinates and limit become $$\lim_{r\to 0}\frac{2\cos \theta}{r^2+\cos\theta}=\frac{2\cos \theta}{\cos\theta}=2$$ and argue the result that by the method above we sweeps out entire plane so we can do like this.But i did like this.I chose family of path given by $y^2=mx$ and put it in limit,then I got given limit as $\lim_{x\to0}\frac{2}{x+m+1}=\frac{2}{m+1}$ which depends on m which means limit doesn't exist.What is correct??Is there any general method to find existence and value of limit.I know $\epsilon-\delta$ method but for that we must know the limit.Therefore how to find limit if we don't know that.Is polar conversion helps with this problem?If one find limit as existing from any method,how can we sure that we will find limit existing and unique in other method also?

Best Answer

There is no limit. Choose $x>0, m>0$, and $y=\sqrt{mx}$, then ${2x \over x^2 +x + y^2} = {2x \over x^2+(1+m)x} = { 2 \over x+(1+m)}$, and $\lim_ {x \downarrow 0} { 2 \over x+(1+m)} = { 2 \over 1+m}$. Since $m>0$ was arbitrary, there is no limit of the original function.

Your friend's technique would need to allow $\theta$ to be arbitrary as well, otherwise the limit is only taken over radial lines.

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