-
Given an irregular polygon where all of the angles are known, how many side lengths need to be known, at minimum, to determine the length of the remaining sides?
-
Given all the angles and the requisite number of side lengths, how to actually calculate the remaining side length?
Example: a 5 Sided polygon's interior angles will add up to 540 degrees. ((5-2)*180=540)
.
Given the following interior angles:
AB 140 degrees
BC 144 degrees
CD 78 degrees
DE 102 degrees
EA 76 degrees
And knowing that Side A is 12 units long, can we determine the remaining side lengths? Or are more side lengths needed?
UPDATE:
Since you need three consecutive side lengths of a five sided figure, I'm adding three sides here so I can see an example of how the calculations are done for the remaining two sides:
Side A = 27 7/8"
Side B = 7"
Side c = 13 1/4"
Best Answer
For a $n$ sided polygon, you need all the angles in order and $n-2$ consecutive side lengths in order to construct the polygon. So, you need the lengths of sides $B,C$ or $E,B$ or $D,E$ to construct your polygon.
The best way to find out the length of the remaining side is by drawing diagonals and applying triangle laws (sine or cosine rule).
Consider the (very badly drawn) pentagon. It is not drawn to scale, but you get the idea. Here are the steps you will take to find out the lengths of $D,E$.