Taylor series (centered at -1) is given by:
$$ \sum_{n=1}^\infty \frac{(n+1)}{n}(x+1)^n $$
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what function centered at -1 does this series represent?
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hints as to how I may find its interval of convergence is (-2,0)?
calculussequences-and-seriestaylor expansion
Taylor series (centered at -1) is given by:
$$ \sum_{n=1}^\infty \frac{(n+1)}{n}(x+1)^n $$
what function centered at -1 does this series represent?
hints as to how I may find its interval of convergence is (-2,0)?
Best Answer
Hint: Let $w=1+x$. Note that $\dfrac{n+1}{n}=1+\dfrac{1}{n}$.
So our sum is $$\sum_1^\infty w^n +\sum_1^\infty \frac{1}{n}w^n.$$ The first sum will be very familiar. For the second, note that $\dfrac{w^n}{n}$ is an antiderivative of $w^{n-1}$.
For convergence, you are interested in showing that the interval is $-1\lt w\lt 1$. Ratio test will do it, except that you need to show also that we do not have convergence at $w=\pm 1$.