So I'm taking calculus 2, having never taken physics and I'm having some trouble understanding the problems we are at.
I'm trying use integrals to calculate the force required to pump a container of water.
So far my teacher states that given the density of water $\rho = 1000\ \mathrm{kg/m^3}$ and the gravitational acceleration of the earth $g = 0.8\ \mathrm{m/s^2}$ we can determine that $1\ \mathrm m^3$ weighs $1000\ \mathrm g$ which is around $9800\ \mathrm N$.
I can't seem to figure out how he got to $9800\ \mathrm N$.
I'm trying to play with the density of water and the gravitational acceleration to get to 9800, but my units don't seem to add up.
Best Answer
Well the force of gravity is equal to $mg=\rho V g=(1000 kg/m^3)(1 m^3)(9.8kg *m/s^2)=9800N$.