For the differential equation $\frac{dy}{dx}=\sqrt{y^2-25}$ does the existence/uniqueness theorem guarantee that there is a solution to this equation through the point
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(-1,28)
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(0,5)
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(3,-5)
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(1,34)
given that $\frac{dy}{dx}=f(x,y)=\sqrt{y^2-25}$
$f'=\frac{2y}{\sqrt{y^2-25}}$
this means as existence and uniqueness theorem the interval containing 5 is not have solution i am right
Best Answer
On solving the differential equation, we get $$\ln|y+\sqrt{y^2-25}|=x+c$$ Now if you put the $4$ points here, do you get real finite values of $c$?