$$x^2 = (x+1)^2 + (x-7)^2$$
can someone please find $x$? Also this is a quadratic equation problem solving question.
[Math] Finding x using the pythagoras theorem
problem solvingpythagorean triplesquadratics
problem solvingpythagorean triplesquadratics
$$x^2 = (x+1)^2 + (x-7)^2$$
can someone please find $x$? Also this is a quadratic equation problem solving question.
Best Answer
We don't need the Pythagorean theorem to solve this. It's just a quadratic equation. $$x^2 = (x+1)^2 + (x-7)^2 = x^2 + 2x + 1 + x^2 - 14x + 49$$ Rearranging, we get $$x^2 - 12x + 50 = 0$$ Now you can use the quadratic formula.