There are two quadratic polynomials (dividends). These two polynomials are divided by two different linear polynomials like $x+1$ (divisors). The remainders are known, but the quotients are unknown.
For example:
$$\dfrac{ax^2 + bx + 1}{x+1} \text{ gives remainder } 3$$
and
$$\dfrac{bx^2 + ax + 2}{x-2} \text{ gives remainder } 2$$
I have been thinking about the Remainder Theorem. However, since there are two unknowns in the quadratic polynomials plus the unknown quotients, it seems we have fewer simultaneous equations than unknowns to solve for.
Best Answer
The Remainder Theorem, usually presented in connection with Synthetic Division, tells us that dividing a polynomial $p(x)$ by a monic first-degree polynomial $x-r$ gives us a (constant) remainder $p(r)$, the polynomial $p(x)$ evaluated at $x=r$.
So the first relation tells us about $ax^2 + bx + 1$ being evaluated at $x=-1$ (we should get $3$), and the second relation says $bx^2 + ax + 2$ evaluated at $x=2$ should get $2$.
Now you have two equations in two unknowns, $a$ and $b$, so there's a chance this gives a unique solution.