find the radius of the circle with center at (-1,2) if a chord of length 10 is bisected at (4,-3).(this is exactly what our professor given to us)
im thinking of using the distance formula which is
d=√(x2-x1)^2+(y2-y1)^2
but our topic is about division of line segment but i think i cant use that because the problem is about finding the length of radius of a circle
link of the formula
and ive tried to graph it, but i dont know if it is correct.
this is according on my understanding
Best Answer
As the perpendicular bisector of any chord of any given circle must pass through the center O$(-1,2)$ of that circle.
If $P(4,-3)$ is midpoint of the chord and $R$ is one of the extreme points,
$OR^2=OP^2+PR^2, PR=5$ unit