Find compound interest on $\$7500$ at $4\%$ per annum for $2$ years, compounded annually.
The choices are as follow: $\$512$, $\$552$, $\$612$, $\$622$.
I tried to solve this problem by:
C.I. $= 7,500(.02) = 150$
C.I. $= 7650 (.02) = 153$
So, $150 + 153 = 303$.
The answer key given to us states that the answer is $\$612$. Here is its solution:
Amount $=7500(1 + 4/100)2$
i.e. $= 7500(26/25)(26/25) \rightarrow 8112$
C.I. $= 8112 – 7500$
C.I. $= 612$
Please help me reconcile this solution with the one I have. Where Were I mistaken?
PS I am a college student having troubles with word problems.
Best Answer
You wrote
In particular you used (.02) there. The problem stated however "4% per annum", so you should have used (.04) instead.
7500(.04) = 300
7800(.04) = 312
300+312 = 612
Your answer and method would have been correct if the problem read "Find compound interest on 7500 dollars at 2% per annum for 2 years, compounded annually." or if it read as "Find compound interest on 7500 dollars at 4% per annum for 1 year, compounded semi-annually."
Edit: In response to your question on how to interpret the answer key's solution.
[7500(1 + 4/100)2], although poorly typed is meant to be $7500\cdot(1+\frac{4}{100})^2$
In this case, $P=7500$, $r=.04$, $n=1$, and $y=2$, and $F$ is unknown. So, by the formula above, $F=7500(1+.04)^2$. With a bit of arithmetical simplifications, $=7500(1.04)^2 = 7500(\frac{26}{25}\cdot\frac{26}{25})$
Often times you will see the formula rewritten as $F = P(1+i)^t$ where $i$= interest rate per payment period = $\frac{r}{n}$, and $t$ = number of payment periods = $n\cdot y$.