$r=e^θ $ $($ Assume $0 ≤ θ ≤ 2π.)$
Apparently I keep getting this answer wrong. I dont know if i need to use $n $ in the answer or not…
calculustrigonometry
$r=e^θ $ $($ Assume $0 ≤ θ ≤ 2π.)$
Apparently I keep getting this answer wrong. I dont know if i need to use $n $ in the answer or not…
Best Answer
In Cartesian form $y=e^\theta\sin\theta$ and $x=e^\theta\cos\theta$
Now, $$\frac{dy}{dx}=\frac{\frac{dy}{d\theta}}{\frac{dx}{d\theta}}=\frac{\sin\theta +\cos\theta}{\cos\theta - \sin\theta }$$
Tangent is horizontal when numerator is $0$ which gives $\theta=7\pi/4,3\pi/4$
and Tangent is vertical when denominator is $0$ which gives $\theta=\pi/4, 5\pi/4$