IF $x , y , z$ are arbitary positive real numbers satisfying the equation
$$ 4xy + 6yz + 8xz = 9$$
Find the maximum value of the product $xyz$.
I dont know from where to begin .
3 variables and one equation.
How I can achieve this?
algebra-precalculusinequality
IF $x , y , z$ are arbitary positive real numbers satisfying the equation
$$ 4xy + 6yz + 8xz = 9$$
Find the maximum value of the product $xyz$.
I dont know from where to begin .
3 variables and one equation.
How I can achieve this?
Best Answer
Arithmetic mean is $\ge$ Geometric mean, i.e. $${{4xy + 6yz + 8xz}\over3} \ge {{(4xy\cdot 6yz\cdot 8xz)}}^{1/3}.$$