I have a fairly simple question which I just can not figure out how to solve – this is the question:
A particle travels along a straight line with its velocity at time 't' seconds given by 'v' m/s where v = 4t + 1. Find the distance traveled in the fifth second.
Any help would be appreciated, thanks.
Best Answer
You should remember the following:
When we differentiate a function expressing the displacement of a particle, we get the function giving the velocity of the particle.
When we differentiate a function expressing the velocity of a particle, we get the function giving the acceleration of the particle.
As long as $t$ is present in the function we get upon Differentiating we can plug in $t=k$ to get the velocity or acceleration at time $t=k$.
$$\Rightarrow \text{Displacement over the time interval }t=4\text{ and }t=5 =\int_4^5 4t+1 dt$$ $$\bigg (2t^2+t\bigg )\bigg|^{t=5}_{t=4}$$