find the area of the shaded region $$x=y^2-1, y=1, x=\sqrt y$$
The shaded region contains the point $(0,1)$
$$y=\sqrt{x+1}, y=x^2, y=1$$
$$\int _{-1}^{1}\left(\sqrt{x+1}-1-x^2\right)dx$$
I'm getting something different than the book
areacalculusdefinite integrals
find the area of the shaded region $$x=y^2-1, y=1, x=\sqrt y$$
The shaded region contains the point $(0,1)$
$$y=\sqrt{x+1}, y=x^2, y=1$$
$$\int _{-1}^{1}\left(\sqrt{x+1}-1-x^2\right)dx$$
I'm getting something different than the book
Best Answer
Hint:
$$\int_0^1 \sqrt{y}-(y^2-1) \, dy$$