Geometry – How to Find the Area of the Shaded Region
areageometry
Find the area of the shaded region in the figure below:
I am completely stuck on how to start off this question. Please help on some guidance on how to start it off.
Best Answer
Split the square into $8$ triangles, convince yourself you can group them into 4 pairs
and each pair has same area. Let the area of the triangles be $a, b, c, d$ as illustrated above.
You are given $c + d = 20$, $b + c = 32$ and $a + d = 16$. The area of the quadrilateral (in cyan) is
$$a + b = (a + d) + ( b + c) - ( c + d) = 16 + 32 -20 = 28$$
$$
\begin{align}
\text{red area} &= \text{area of }\Delta ABC + \text{area of semi-circle} - \text{area of quadrant} \\
&= \tfrac12 \times 21 \times 28 + \tfrac12 \pi \left(\tfrac{35}{2}\right)^2 - \tfrac14 \pi (21)^2 \\
&= 294 + 481.0563 - 346.3606 \\
&= 428.6957
\end{align}
$$
So it looks like you are right and your book is wrong.
Hint: Break the shaded region up into two shapes. One is a portion of the circle (you know the portion because of the given angle), and the other is a triangle (which is equilateral). Find the area of each shape and then add them.
Best Answer
Split the square into $8$ triangles, convince yourself you can group them into 4 pairs and each pair has same area. Let the area of the triangles be $a, b, c, d$ as illustrated above.
You are given $c + d = 20$, $b + c = 32$ and $a + d = 16$. The area of the quadrilateral (in cyan) is $$a + b = (a + d) + ( b + c) - ( c + d) = 16 + 32 -20 = 28$$