Find the points on the graph of $y = x^{2}+2x+6 $at which the slope of the tangent line is equal to $4$
Just starting to learn calculus. This is what I have done so far.
Take the Derivative $f '(x) = 2x+2$. So if I plug in $1$ for $x$, I get $4$, so my first point is $(1,y)$. How do I get the Y coordinate?
Best Answer
Since you know that the $x$ coordinate giving the right slope is $1$the point on the graph will be $(1,f(1))=(1,9)$.