I've been stuck on this final math problem for ages
I'm given $$f(x) = x^2 + 1$$
and the final composition is $$(g \circ f)(x) = \frac{1}{x^2 + 4}$$
I'm asked to find that $g(x)$ was in order to make this true, but i'm not sure how?
functions
I've been stuck on this final math problem for ages
I'm given $$f(x) = x^2 + 1$$
and the final composition is $$(g \circ f)(x) = \frac{1}{x^2 + 4}$$
I'm asked to find that $g(x)$ was in order to make this true, but i'm not sure how?
Best Answer
Here's my reasoning:
$$ g(f(x)) = \frac{1}{x^2 + 4} = \frac{1}{(x^2+1)+3}$$
Since $x^2 + 1 = f(x)$
$$g(f(x)) = \frac{1}{f(x)+3} \implies g(x) = \frac{1}{x+3} $$
With $g(x)$, Note: $x \ne -3$ $(x \in \mathbb{R})$