$$\int \sqrt{5 + 4x – x^2}dx$$
I am pretty certain what I need to do to this problem is complete the square and turn it into a trig subsitution but I have no idea how to complete the square with a $-x^2$ or really with this problem at all, I just can't make it work.
I tried to see if I could make the problem be the same in any way by just pulling out a negative but that didn't seem to work.
I got the problem up to
$$\int \sqrt{ -1(x-2)^2 – 1}dx$$
But I do not think that does me any good. What I think I need to do is have a difference of squares with a square in it or something, I just have to get rid of the 4x term somehow.
Best Answer
Firstly, it should be
$$ \int \sqrt{5 + 4 + (-4) + 4x - x^2} dx = \int \sqrt{5 + 4 - (x^2 - 4x + 4}) dx = \int \sqrt{9 - (x - 2)^2}dx $$
Next a hint. Let $3\sin \theta = x-2$.